fix(arr.at): 低版本安卓浏览器打包报错
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@ -1,4 +1,11 @@
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import { pages, subPackages, tabBar } from '@/pages.json'
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import { pages, subPackages, tabBar } from '@/pages.json'
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const getLastPage = () => {
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// getCurrentPages() 至少有1个元素,所以不再额外判断
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// const lastPage = getCurrentPages().at(-1)
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// 上面那个在低版本安卓中打包回报错,所以改用下面这个【虽然我加了src/interceptions/prototype.ts,但依然报错】
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const pages = getCurrentPages()
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return pages[pages.length - 1]
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}
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/** 判断当前页面是否是tabbar页 */
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/** 判断当前页面是否是tabbar页 */
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export const getIsTabbar = () => {
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export const getIsTabbar = () => {
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@ -9,8 +16,7 @@ export const getIsTabbar = () => {
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// 通常有tabBar的话,list不能有空,且至少有2个元素,这里其实不用处理
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// 通常有tabBar的话,list不能有空,且至少有2个元素,这里其实不用处理
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return false
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return false
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}
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}
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// getCurrentPages() 至少有1个元素,所以不再额外判断
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const lastPage = getLastPage()
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const lastPage = getCurrentPages().at(-1)
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const currPath = lastPage.route
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const currPath = lastPage.route
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return !!tabBar.list.find((e) => e.pagePath === currPath)
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return !!tabBar.list.find((e) => e.pagePath === currPath)
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}
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}
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@ -21,8 +27,7 @@ export const getIsTabbar = () => {
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* redirectPath 如 ‘/pages/demo/base/route-interceptor’
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* redirectPath 如 ‘/pages/demo/base/route-interceptor’
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*/
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*/
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export const currRoute = () => {
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export const currRoute = () => {
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// getCurrentPages() 至少有1个元素,所以不再额外判断
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const lastPage = getLastPage()
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const lastPage = getCurrentPages().at(-1)
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const currRoute = (lastPage as any).$page
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const currRoute = (lastPage as any).$page
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// console.log('lastPage.$page:', currRoute)
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// console.log('lastPage.$page:', currRoute)
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// console.log('lastPage.$page.fullpath:', currRoute.fullPath)
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// console.log('lastPage.$page.fullpath:', currRoute.fullPath)
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